Answer:
The instantaneous velocity after eight seconds is 9 m/s
Step-by-step explanation:
Given as :
The ball shot upward with velocity of 15 m/s
The height of the ball after t sec is given as h(t) = [tex]10 + 5t + \frac{1}{4}t^{2}[/tex]
Now, The instantaneous velocity after 8 sec = [tex]\frac{\partial h(t)}{\partial t}[/tex]
Or, The instantaneous velocity = [tex]\frac{\partial (10 +5t + \frac{1}{4}t^{2})}{\partial t}[/tex]
or, The instantaneous velocity = [tex]5 + \frac{1}{4}\times 2 t[/tex]
Now at t = 8 sec
The instantaneous velocity = 5 + 4 = 9 m/s
Hence The instantaneous velocity of ball at t = 8 sec , is 9 m/s Answer
