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a 500 kg piano is being lowered into position by a crane while two people steady it with ropes pulling to the sides. bobs rope pulls to the left, 15 degrees below horizontal, with 410 N of tension. Ellen's rope pulls toward the right, 26 degrees below horizontal.

Part A
What tension must Ellen maintain in her rope to keep the piano de ending at a steady speed?

PartB
What is the tension is the vertical main cable supporting the piano?

Respuesta :

Answer:

(a). The tension must Ellen maintain in her rope to keep the piano the ending at a steady speed is 440.6 N

(b). The tension is the vertical main cable supporting the piano is 5489.17 N

Explanation:

Given that,

Mass of piano = 500 kg

Tension = 410 N

We need to calculate the tension must Ellen maintain in her rope to keep the piano the ending at a steady speed

Using balance equation

[tex]F_{b}\cos15=F_{e}\cos26[/tex]

[tex]F_{e}=\dfrac{F_{b}\cos15}{\cos26}[/tex]

[tex]F_{e}=\dfrac{410\cos15}{\cos26}[/tex]

[tex]F_{e}=440.6\ N[/tex]

(b). We need to calculate the tension is the vertical main cable supporting the piano

Now,tension in the rope is T

Vertical forces acting on the piano are

[tex]T=mg+F_{b}\cos\theta+F_{e}\sin\theta[/tex]

Put the value into the formula

[tex]T=500\times9.8+410\cos15+440.6\sin26[/tex]

[tex]T=5489.17\ N[/tex]

Hence, (a). The tension must Ellen maintain in her rope to keep the piano the ending at a steady speed is 440.6 N

(b). The tension is the vertical main cable supporting the piano is 5489.17 N

pyamupom

Answer:

The answer above is incorrect because the degrees are switched. If you switch the 15 degrees and 26 degrees and substitute them into where they are incorrectly placed, then you get the correct answer.

Explanation: