Answer:
given,
Cavendish is placed at 0.05 m
mass of small sphere = m₁ = 0.01 Kg
mass of large sphere = m₂ = 0.5 Kg
magnitude of acceleration = ?
Force calculation
[tex]F = \dfrac{Gm_1m_2}{r^2}[/tex]
[tex]F = \dfrac{6.67 \times 10^{-11}\times 0.01 \times 0.5}{0.05^2}[/tex]
[tex]F =1.33 \times 10^{-10}\ N[/tex]
acceleration of the smaller sphere
[tex]a = \dfrac{F}{m}[/tex]
[tex]a = \dfrac{1.33 \times 10^{-10}}{0.01}[/tex]
[tex]a =1.33 \times 10^{-8}\ m/s^2[/tex]
acceleration of the bigger sphere
[tex]a = \dfrac{F}{m}[/tex]
[tex]a = \dfrac{1.33 \times 10^{-10}}{0.5}[/tex]
[tex]a =2.66\times 10^{-10}\ m/s^2[/tex]
