Answer:
0.25683
Explanation:
t = Time taken by the truck to stop = 11 seconds
u = Initial velocity of the truck = 62 mi/h
v = Final velocity of the truck = 0
a = Acceleration of the truck
g = Acceleration due to gravity = 9.81 m/s²
Equation of motion
[tex]v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{0-\frac{62}{2.237}}{11}\\\Rightarrow a=-2.5196\ m/s^2[/tex]
[tex]\mu mg=ma\\\Rightarrow \mu=\frac{ma}{mg}\\\Rightarrow \mu=\frac{a}{g}\\\Rightarrow \mu=\frac{2.5196}{9.81}\\\Rightarrow \mu=0.25683[/tex]
The minimum coefficient of static friction between the turtle and the truck bed surface needed to prevent the turtle from sliding is 0.25683
