I need help with my math homework...

Answer:
Step-by-step explanation:
7a) From the graph
y =0.6782x +4.26
Comparing with the slope intercept equation, y=mx+c,
m = slope = 0.6782
The slope represents the rate at which the profit is increasing as the year increases. The slope shows that this rate is constant. The profit increases with respect to the number of years after startup at a constant rate of 0.6782
7b) for x= 5years,
y =0.6782 ×5 +4.26= 7.651
It's the same as the actual data point from the graph. The difference could be very minimal
8) General formula is
y = bx +a
y is the dependent variable
x is the independent variable
9)the loss rate follow arithmetic progression
Tn = a+(n-1)d
Where Tn =0( no money)
a = 336700( amount left as savings before losing)
d= -9100 ( difference between the second term - the first term).it is decreasing at a negative rate.
n = number of years
0=336700+ (n-1)-9100
0=336700-9100n +9100
9100n=336700 +9100=345800
n = 38years
10)It also follows arithmetic progression
number of years =2015-1980=35
d =2
a = 100
We are looking for Tn, the nth term
Tn =a+(n-1)d= 100+(35-1)2
=100+68
=168 geese in 2015