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A particular uniform solid disk has a mass of 24.0 kg and a radius of 1.50 m. The disk is rotating about an axle passing through the center of the disk. The axis of rotation is perpendicular to the plane of the disk, as you might expect. At a particular instant in time, the disk's angular speed is 3.00 rad/s. At that same instant, what is the magnitude of the disk's angular momentum, relative to the disk's axis of rotation? _______ m^2/s^2

Respuesta :

lcmendozaf

Answer:

[tex]L = 81 Kg.m^2/s^2[/tex]

Explanation:

Angular momentum is calculated as:

L = I * ω

The inertia of the disc is:

[tex]I = 1/2 * M *R^2 = 1/2 * 24 * (1.5)^2=27Kg.m^2[/tex]

So, the angular momentum is:

[tex]L = 27 Kg.m^2* 3rad/s=81Kg.m^2/s^2[/tex]