Respuesta :
Answer:
U = 9253.6 J
Explanation:
It is given that,
Heat transferred in isochoric process, [tex]Q_1=5560\ J[/tex]
Pressure in this process, [tex]P_1=3.32\times 10^5\ Pa[/tex]
In the second step,
It is subjected to isobaric compression until its volume decreases by, [tex]V=-7.3\times 10^{-3}\ m^3[/tex] (it decreases)
Heat transferred out of the gas, [tex]Q_2=1270\ J[/tex]
In isochoric process, work done by the gas is zero as in this type volume is constant, [tex]W_1=0[/tex]
According to first law of thermodynamics,
[tex]\Delta U=Q-W[/tex]
[tex]\Delta U_1=5560\ J[/tex].............(1)
In isochoric compression, [tex]W_2=P\Delta V[/tex]
[tex]\Delta U_2=1270-3.32\times 10^5\times (-7.3\times 10^{-3})[/tex]
[tex]\Delta U_2=3693.6\ J[/tex]
Let U is the total change in the internal energy of this gas. So,
[tex]U=U_1+U_2[/tex]
[tex]U=5560+3693.6[/tex]
U = 9253.6 J
So, the total change in the internal energy of this gas is $9253.6 J. Hence, this is the required solution.
