Answer
a) charge of the sodium ion is,
q = n e
q = 2.68 x 10¹⁶ x 1.6 x 10⁻¹⁹
q = 4.288 x 10⁻³ C
charge of the chlorine ion is,
q' = n e
q' = 3.92 x 10¹⁶ x 1.6 x 10⁻¹⁹
q' = 6.272 x 10⁻³ C
the current
[tex]i = \dfrac{q}{t} + \dfrac{q'}{t}[/tex]
[tex]i = \dfrac{4.288 \times 10^{-3}}{1} + \dfrac{6.272 \times 10^{-3}}{1}[/tex]
[tex]i = 10.56 \times 10^{-3} [/tex]
b) positive ion moves toward negative electrode hence direction of will be in the direction toward negative electrode.
