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What is the equation of this line in slope-intercept form? y=−3x−1 y = 3x + 1 y=3x−1 y=− 1 3 x−1

idk how to screenshot the graph but here are the points and options

(-1,2) and (1,-4) are the points

and these are the options

y=-3x-1
y=3x+1
y=3x-1
y=-1/3x-1

PLEASE HELP ASAP

Respuesta :

calculista

Answer:

[tex]y=-3x-1[/tex]

Step-by-step explanation:

we know that

The equation of a line in slope intercept form is

[tex]y=mx+b[/tex]

where

m is the slope

b is the y-intercept

we have the points

(-1,2) and (1,-4)

step 1

Find the slope m

The formula to calculate the slope between two points is equal to

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

substitute the values

[tex]m=\frac{-4-2}{1+1}[/tex]

[tex]m=\frac{-6}{2}[/tex]

[tex]m=-3[/tex]

step 2

Find the y-intercept b

we have

[tex]m=-3[/tex]

point (-1,2)

substitute

[tex]y=mx+b[/tex]

[tex]2=-3(-1)+b[/tex]

solve for b

[tex]2=3+b[/tex]

[tex]b=-1[/tex]

The equation of the line is

[tex]y=-3x-1[/tex]