The car takes 10.8 seconds to reach a velocity of 42.1 m/s
Explanation:
The motion of the car is at constant acceleration, so we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity of the car
u is its initial velocity
a is the acceleration
t is the time
For the car in this problem, we have:
u = 15.0 m/s
v = 42.1 m/s
[tex]a=2.50 m/s^2[/tex]
Solving for t, we find the time it takes for the car to reach that velocity:
[tex]t=\frac{v-u}{a}=\frac{42.1-15.0}{2.50}=10.8 s[/tex]
Learn more about acceleration here:
brainly.com/question/9527152
brainly.com/question/11181826
brainly.com/question/2506873
brainly.com/question/2562700
#LearnwithBrainly
