Respuesta :
Answer:
(a). The block's acceleration be if the surface were friction less is 8 m/s².
(b). The kinetic friction force is 10 N.
(c). The coefficient of kinetic friction is 0.2
Explanation:
Given that,
Force = 40.0 N
Acceleration = 6.0 m/s²
Mass = 5.0 kg
(a). We need to calculate the block's acceleration be if the surface were friction less
Using formula of force
[tex]F= ma[/tex]
Where, m = 5.0 kg
F = 40.0 N
[tex]40.0= 5.0\times a[/tex]
[tex]a=\dfrac{40.0}{5.0}[/tex]
[tex]a=8\ m/s^2[/tex]
(b). We need to calculate the kinetic friction force
Using formula of frictional force
[tex]f_{k}=F-ma[/tex]
Put the value into the formula
[tex]f_{k}=40-5.0\times6.0[/tex]
[tex]f_{k}=10\ N[/tex]
(c). We need to calculate the coefficient of kinetic friction
Using formula of friction formula
[tex]f_{k}=\mu mg[/tex]
[tex]\mu=\dfrac{f_{k}}{mg}[/tex]
[tex]\mu=\dfrac{10}{5.0\times9.8}[/tex]
[tex]\mu=0.2[/tex]
Hence, (a). The block's acceleration be if the surface were friction less is 8 m/s².
(b). The kinetic friction force is 10 N.
(c). The coefficient of kinetic friction is 0.2
A force of 40.0 N accelerating a 5.0-kg block at 6.0 [tex]m/s^2[/tex] along a horizontal surface has the following parameters:
a. Acceleration = 8 [tex]m/s^2[/tex]
b. Kinetic friction force, Fk = 10 Newton.
c. Coefficient of kinetic friction, u = 0.2040.
Given the following data:
Force = 40.0 Newton
Acceleration = 6.0 [tex]m/s^2[/tex]
Mass of block = 5 kg
a. To find the block's acceleration if the surface were frictionless, we would apply Newton's Second Law of Motion:
[tex]Acceleration = \frac{Force}{Mass}\\\\Acceleration = \frac{40}{5}[/tex]
Acceleration = 8 [tex]m/s^2[/tex]
b. To find the kinetic friction force, we would apply the frictional force formula:
[tex]F_k = Force - (ma)\\\\F_k = 40 - (5[6])\\\\F_k = 40 - 30[/tex]
Kinetic friction force, Fk = 10 Newton
c. To find the coefficient of kinetic friction:
[tex]u = \frac{F_k}{mg}\\\\u = \frac{10}{5[9.8]}\\\\u = \frac{10}{49}[/tex]
Coefficient of kinetic friction, u = 0.2040.
