Respuesta :

AL2006

-- When he's at rest, his kinetic energy is zero.

-- When he reaches 6.5 m/s, his kinetic energy is . . .

KE = (1/2) (m) (v²)

KE = (34 kg) (42.25 m²/s²)

KE = 1,436.5 Joules

That's the amount of energy that has to come from somewhere, in order to boost him to that speed.

The Kinetic energy will be "1436.5 Joules".

Given values are:

Mass,

  • m = 68 kg

Speed,

  • v = m/s

As we know the formula,

→ [tex]Kinetic \ energy = \frac{1}{2}mv^2[/tex]

By substituting the given values, we get

→                           [tex]= \frac{1}{2} (68)(6.5)^2[/tex]

→                           [tex]= \frac{1}{2}\times 68\times 42.25[/tex]

→                           [tex]= 34\times 42.25[/tex]

→                           [tex]= 1436.5 \ Joules[/tex]

Thus the above answer is appropriate.

Learn more about K.E here:

https://brainly.com/question/8168245