Answer:4.259 kN
Explanation:
Given
mass of bullet [tex]m=0.02 kg[/tex]
final velocity of bullet [tex]v=575 m/s[/tex]
time taken [tex]=2.7 ms\approx 2.7\times 10^{-3} s[/tex]
We know
[tex]Impulse=F_{avg}\cdot t=change\ in\ momentum[/tex]
thus
Initial Momentum[tex](P_i)=m\times 0[/tex]
Final Momentum[tex](P_f)=m\times v=0.02\times 575[/tex]
[tex]P_f=11.5 kg-m/s[/tex]
[tex]F_{avg}\times 2.7\times 10^{-3}=P_f-P_i=11.5[/tex]
[tex]F_{avg}=4.259\times 10^3[/tex]
[tex]F_{avg}=4.259 kN[/tex]
