Respuesta :
Answer:
a). 8.345v
b). 688.025 - 8.345v
c). 312.5 pounds
d). 21 gallons
Step-by-step explanation:
A bathtub contains amount of water = 45 gallons
And 1 gallon of water weighs = 8.345 pounds
Amount of water drained from the tub since the plug was pulled = v gallons
a) Therefore, weight of v gallons of water drained = 8.345v
b). Since total weight of the tub and water = 688.025 pounds
8.345v pounds of water is drained so total weight of tub and water will be = 688.025 - 8.345v
c). Total weight of the tub when v = 45 or the tub is empty.
Weight of the empty tub = 688.025 - 8.345(45)
= 688.025 - 375.525
= 312.5 pounds
d). If the weight of the tub and water is 487.745 pounds then we have to determine the amount of water drained from the tub.
Let the number gallons of water in the tub is w, then the weight of w gallons water = 8.345w pounds
Weight of the water and tub = weight of water + weight of the tub
487.745 = 8.345w + 312.5
8.345w = 487.745 - 312.5
8.345w = 175.245
w = [tex]\frac{175.45}{8.345}[/tex]
w = 21 gallons
a). 8.345v
b). 688.025 - 8.345v
c). 312.5 pounds
d). 21 gallons
- The calculation is as follows:
a) The weight of v gallons of water drained = 8.345v
b). Since total weight of the tub and water = 688.025 pounds
So, the equation is
= 688.025 - 8.345v
c). Total weight of the tub when v = 45 or the tub is empty.
Weight of the empty tub = 688.025 - 8.345(45)
= 688.025 - 375.525
= 312.5 pounds
d).
Let the number gallons of water in the tub is w, then the weight of w gallons water = 8.345w pounds
Now
Weight of the water and tub = weight of water + weight of the tub
487.745 = 8.345w + 312.5
8.345w = 487.745 - 312.5
8.345w = 175.245
w = 21 gallons
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