Respuesta :
Answer: Heat of reaction ∆H = -13.43kJ
Explanation:
The number of moles of NaOH = the number of moles of HCL = N
N = concentration × volume= CV = 0.5M × 500mL/1000ml/L
N= 0.5 × 0.5= 0.25mol
Since the Molar enthalpy is given by Hm = -53.72kJ/mol
Heat of reaction ∆H = N×Hm
∆H= 0.25mol × -53.72kJ/mol = -13.43kJ
Heat of reaction ∆H = -13.43kJ
Heat of reaction ∆H = -13.43kJ
The number of moles of NaOH = the number of moles of HCL = N
N = concentration × volume= CV = [tex]\frac{0.5M * 500mL}{1000ml/L}[/tex]
N= [tex]0.5 * 0.5= 0.25mol[/tex]
Given:
Molar enthalpy, [tex]H_m = -53.72kJ/mol[/tex]
Heat of reaction:
It is the amount of heat that must be added or removed during a chemical reaction in order to keep all of the substances present at the same temperature.
Heat of reaction, [tex]\triangle H = N*H_m[/tex]
[tex]\triangle H= 0.25mol * -53.72kJ/mol \\\\\triangle H= -13.43kJ[/tex]
Thus, Heat of reaction, [tex]\triangle H = -13.43kJ[/tex]
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