4 letters are typed, without repetition. What is the probability that all 4 will be vowels? Write your answer as a percent. Round your answer to three decimal places

Respuesta :

Answer:

0,026%

Step-by-step explanation:

We have 26 letters in the alphabet and 5 of them are vowels.

When typing the first letter, we need it to be a vowel. As there are 5 vowels, the probability of one of them being typed is 5/26 (we have 5 right options in a total of 26).

Now, when typing the 2nd letter, we will assume that we already had typed a vowel because that's what we need. So now we have 4 options to be typed because we can't repeat the vowel. The probability of getting a vowel on the 2nd place is 4/26.

On the 3rd place we will have 3 vowels available and the probability of typing another vowel is 3/26.

On the 4th place we will have 2 vowels available and the probability of typing another vowel is 2/26.

As we need this to happen all at the same time, we need to multiply all the probabilities. That is

5/26 * 4/26 * 3/26 * 2/26 = 0,026%

Therefore, the probability of the 4 will be vowels is 0,026%.

Answer:

2/13; 15.38%; 0.154

Step-by-step explanation:

Since total number of letters in the alphabet is equal to 26, this will give the total outcome.

If 4 letters are typed, without repetition, the expected outcome is 4 since there are no repetition.

Probability = expected number of outcome/total number of outcome

Probability that all 4 will be vowels will be;

P(all vowels) = 4/26 = 2/13

Expressing 2/13 as percent, we will have;

2/13 × 100

= 200/13

= 15.38%

Expressing 2/13 as decimal will give;

2/13 = 0.1538

2/13 = 0.154( to 3 decimal places)

Note that the third digits after the decimal point 3 is rounded off to 4 because the number succeeding it is 8 which greater than 4