Answer
given,
Radius of earth = 6.38 x 10⁶ m
angular velocity = [tex]\omega = \dfrac{2\pi}{day}[/tex]
= [tex]\omega = \dfrac{2\pi}{86400\ s}[/tex]
= [tex]\omega =7.27 \times 10^{-5}[/tex]
a) at equator
velocity v = R ω = 6.38 x 10⁶ x 7.27 x 10⁻⁵
v = 463.8 m/s
centripetal acceleration = R ω² = 6.38 x 10⁶ x (7.27 x 10⁻⁵)²
= 0.0337 m/s²
b) at a latitude of 30.0° north of the equator
r = R cos θ = 6.38 x 10⁶ cos 30⁰ = 3.19 x 10⁶ m
velocity v = R ω = 3.19 x 10⁶ x 7.27 x 10⁻⁵
v = 231.9 m/s
centripetal acceleration = R ω² = 3.19 x 10⁶ x (7.27 x 10⁻⁵)²
= 0.0168 m/s²