contestada

A racquet ball with mass m = 0.223 kg is moving toward the wall at v = 14.7 m/s and at an angle of θ = 27° with respect to the horizontal. The ball makes a perfectly elastic collision with the solid, frictionless wall and rebounds at the same angle with respect to the horizontal. While the ball is in contact with the wall, the average force the wall exerts on the ball has a magnitude of F = 94 N. 1)What is the magnitude of the initial momentum of the racquet ball?

Respuesta :

Answer:

[tex]P_i = 3.2781\ kg.m/s[/tex]

Explanation:

given,

mass of the ball = 0.223 Kg

velocity of the ball toward ball = 14.7 m/s

angle  = θ = 27° w.r.t. horizontal

Average force exerted by the ball on the wall = 94 N

magnitude of initial momentum =

     [tex]P_i = m_iv_i[/tex]

     [tex]P_i = 0.223\times 14.7 [/tex]

     [tex]P_i = 3.2781\ kg.m/s[/tex]

so the initial momentum of the racket ball is [tex]P_i = 3.2781\ kg.m/s[/tex]