Answer:
[tex]4.38958\times 10^{-6}\ T[/tex]
[tex]1316.874\ V/m[/tex]
Explanation:
[tex]\mu_0[/tex] = Vacuum permeability = [tex]4\pi \times 10^{-7}\ H/m[/tex]
I = Flux = 2300 W/m²
c = Speed of light = [tex]3\times 10^{8}\ m/s[/tex]
Amplitude of the oscillating magnetic field
[tex]B_0=\sqrt{\frac{2\mu_0I}{c}}\\\Rightarrow B_0=\sqrt{\frac{2\times 4\pi \times 10^{-7}\times 2300}{3\times 10^8}}\\\Rightarrow B_0=4.38958\times 10^{-6}\ T[/tex]
The amplitude of the oscillating magnetic field is [tex]4.38958\times 10^{-6}\ T[/tex]
Amplitude of the oscillating electric field
[tex]E_0=c\times B_0\\\Rightarrow E_0=3\times 10^{8}\times 4.38958\times 10^{-6}\\\Rightarrow B_0=1316.874\ V/m[/tex]
The amplitude of the oscillating electric field is [tex]1316.874\ V/m[/tex]
