Answer:
The Answer is: There are 5 large boxes and 8 small boxes. (The graphical plot will need to be solved using the software).
Step-by-step explanation:
Let xx = small boxes and yy = large boxes:
xx + yy = 13
xx = 13 - yy
The number of small boxes times 20, plus the number of large boxes times 40 is equal to 360:
20xx + 40yy = 360
Substitute the algebraic value of xx, so we only have one variable to consider and solve for yy:
20(13 - yy) + 40yy = 360
260 - 20yy + 40yy = 360
260 + 20yy = 360
20yy = 100
yy = 100 / 20 = 5 large boxes.
Solve for xx:
xx = 13 - yy
xx = 13 - 5 = 8 small boxes.
There are 5 large boxes and 8 small boxes. (The graphical plot will need to be solved using the software).
Proof:
20xx + 40yy = 360
20(8) + 40(5) = 360
160 + 200 = 360
360 = 360