Answer:
3.6 kg of water is being removed.
Explanation:
Initial weight of food sample = 10 kg
The dry weight is 32% means it has 3.2 kg of dry mass and 6.8 kg of water.
On heating the sample becomes 50% wet basis it means the sample contains 50% dry weight. The earlier dry mass was 3.2 kg, and there will be no change in it.Thus the mass of water will also be 3.2 kg (50%).
The initial mass of water = 6.8 kg
the final mass of water =3.2 kg
The mass of water removed= 6.8 -3.2 = 3.6 kg
The amount of water removed from the 10kg of food at a moisture content of 320% dry basis to 50% wet basis is 3.6kg.
According to this question, 10 kg of food at a moisture content of 320% dry basis is dried to 50% wet basis. This means that:
Initial weight of food sample = 10 kg
The dry weight is 32% meaning it has 3.2 kg of dry mass and 6.8 kg of water.
Heating the sample becomes 50% wet basis it means the sample contains 50% dry weight.
The earlier dry mass was 3.2 kg, and there will be no change in it, hence, the mass of water will also be 3.2 kg (50%).
Therefore, the mass of water removed= 6.8 - 3.2 = 3.6 kg
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