Answer:
37.046 grams of oxygen gas were produced.
Explanation:
[tex]2KClO_2\rightarrow 2KCl+ 3O_2[/tex]
Moles of potassium chlorite = [tex]\frac{82.2 g}{106.5 g/mol}=0.7718 mol[/tex]
According to reaction 2 moles of potassium chlorite gives 3 moles of oxygen gas.
Then 0.7718 moles of potassium chlorite will give:
[tex]\frac{3}{2}\times 0.7718 mol=1.1577 mol[/tex] of oxygen gas.
Mass of 1.1577 moles of oxygen gas:
1.1577 mol × 32 g/mol = 37.046 g
37.046 grams of oxygen gas were produced.