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A conducting wire formed in the shape of a right triangle with base b = 25 cm and height h = 66 cm and having resistance R = 1.1 Ω, rotates uniformly around the y-axis in the direction indicated by the arrow (clockwise as viewed from above (loooking down in the negative y-direction)). The triangle makes one complete rotaion in time t = T = 1.5 seconds. A constant magnetic field B = 1.8 T pointing in the positive z-direction (out of the screen) exists in the region where the wire is rotating. 1)What is ω, the angular frequency of rotation?

Respuesta :

Answer:

[tex]\omega=4.19 \,rad.s^{-1}[/tex]

Explanation:

To find:

angular frequency of rotation, ω=?

Given that:

  • base of wire triangle, b = 25 cm
  • height of wire triangle, h = 66 cm
  • electrical resistance , R = 1.1 Ω
  • time taken to make 1 rotation about the height through the base,T= 1.5s
  • magnetic field in +z direction out of the screen, B = 1.8 T

Since the wire does not carry any current therefore the magnetic field will have no impact on it.

Now, as we know:

angular frequency

[tex]\omega= \frac{2\pi}{T}[/tex]

[tex]\omega=4.19 \,rad.s^{-1}[/tex]