a student walks 144 m west, then turns around and walks 89 m east. if this takes place in a 7.5- minute interval, what is the students average velocity in meters per second? what is the students average speed?

The distance is calculated regardless of the direction of motion. In this problem, the distance walks 144 m first, and then another 89 m, so the total distance covered is

d = 144+89 = 233 m

The time taken is

[tex]t= 7.5 min \cdot 60 = 450 s[/tex]

So, the average speed is

[tex]s=\frac{233}{450}=0.52 m/s[/tex]

2)

The average velocity is calculated as the ratio between the displacement of an object and the time taken:

[tex]v=\frac{displacement}{time}[/tex]

In this case, the students walks 144 m west first, and then 89 m east. The displacement is the distance in a straight line between the initial and final position: therefore, in this case, the displacement is

d = 144 (west) - 89 (east) = 55 m (west)

The time taken is

[tex]t= 7.5 min \cdot 60 = 450 s[/tex]

So, the average velocity is

[tex]v=\frac{55}{450}=0.12 m/s[/tex]

And the direction is west (the same as the displacement).

Learn more about speed and velocity:

brainly.com/question/8893949

brainly.com/question/5063905

brainly.com/question/5248528

#LearnwithBrainly