Answer:
[tex]X'=50.4\,m[/tex]
Explanation:
Given that:
Height of jump, [tex]h=100\,m[/tex]
length of elastic cord, [tex]l=30\,m[/tex]
spring constant of the cord, [tex]k=40\,N.m^{-1}[/tex]
mass of the body that jumps, [tex]m=80\,kg[/tex]
Force on the bungee elastic cord:
[tex]F=m.g[/tex]
[tex]F=80\times 9.8[/tex]
Now this force F will be responsible for the elongation in the elastic cord, so:
[tex]F=k.x[/tex] ............................(1)
where :
k = spring constant
x = extension in the elastic cord
using eq. (1)
[tex]80\times 9.8=40\times x[/tex]
[tex]x=19.6\,m[/tex]
So the cord stretches 19.6 meters more beyond its original length of 30 meters.
Hence, the remaining distance from the river surface at the bottom is:
[tex]X'=100-(30+19.6)[/tex]
[tex]X'=50.4\,m[/tex]