Answer:
Metabolic power 420.138 W
Explanation:
Given data:
considering drag coefficient Cd = 0.9
Assuming cross section of cyclist A = 0.50 m^2
Take density of air ρ = 1.2 kg/m3
We know that drag force is given as
[tex]Drag\ Force = Cd\times 1/2 \times \rho AV^2 [/tex]
[tex]D = 0.9\times 1/2\times 1.2\times 0.5\times 7.3^2 [/tex]
D = 14.388 N
[tex]Power = D\times V = 14.388\times 7.3 = 105.03 W[/tex]
hence metabolic power is given as
Metabolic power [tex]= \frac{D}{\eta}[/tex]
[tex]= \frac{105.03}{0.25}[/tex]
= 420.138 W