volume of H₂ = 78 L
Explanation:
When hydrogen (H₂) react with nitrogen (N₂) it will form ammonia (NH₃):
3 H₂ + N₂ = 2 NH₃
Assuming standard temperature and pressure conditions, we can use the following formula:
number of moles = volume / 22.4 (L/mol)
number of moles of N₂ = 26 / 22.4 = 1.16 moles
Taking in account the chemical reaction, we devise the following reasoning:
if 3 moles of H₂ react with 1 mole of N₂
then X moles of H₂ react with 1.16 mole of N₂
X = (3 × 1.16) / 1 = 3.48 moles of H₂
volume = number of moles × 22.4 (L/mol)
volume of H₂ = 3.48 × 22.4 = 78 L
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