The sprinter takes 1.1 s to accelerate from rest to 10 m/s
Explanation:
The motion of the sprinter is a uniformly accelerated motion (constant acceleration), so we can use the following suvat equation:
[tex]v=u+at[/tex]
where:
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken for the velocity to change from u to v:
For the sprinter in this problem we have:
u = 0 (he starts from rest)
v = 10 m/s
[tex]a=9.5 m/s^2[/tex]
Solving for t, we find the time he takes to reach 10 m/s:
[tex]t=\frac{v-u}{a}=\frac{10-0}{9.5}=1.1 s[/tex]
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