Shown in the figure below
Explanation:
First of all, we have the following equation:
[tex]y=3x-2[/tex]
This is the equation of a line given in Slope-intercept form as the form:
[tex]y=mx+b \\ \\ \\ Where: \\ \\ m:Slope \\ \\ b:y-intercept[/tex]
So this line passes through the point [tex](0,-2)[/tex] which is the y-intercept. To graph this line, we'd need another point. So let set [tex]y=0[/tex]:
[tex]0=3x-2 \\ \\ Isolating \ x: \\ \\ 3x=2 \\ \\ x=\frac{2}{3}[/tex]
So another point is:
[tex](\frac{2}{3},0)[/tex]
Finally, we graph a line that passes through these two points:
[tex](0,-2) \ and \ (\frac{2}{3},0)[/tex]
This is shown in the figure below.
Learn more:
Graph of a line: https://brainly.com/question/13772202#
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