Respuesta :
Answer:
[tex]\angle a \textrm{ and }\angle d; \angle b \textrm{ and }\angle c[/tex]
Step-by-step explanation:
Given:
The triangles are drawn below.
The triangles ABC and DEF are similar.
So, corresponding sides are proportional.
Here, [tex]\frac{AB}{DE}=\frac{6}{3}=2[/tex]
[tex]\frac{BC}{DF}=\frac{8}{4}=2[/tex]
[tex]\frac{AC}{EF}=\frac{4}{2}=2[/tex]
Therefore, [tex]\frac{AB}{DE}=\frac{BC}{DF}=\frac{AC}{EF}=2[/tex]
For similar triangles, the angles opposite corresponding sides are congruent and are called corresponding angles.
So, from the triangle, as sides AB and DE are corresponding sides, therefore, angles b and c are corresponding angles as they are opposite to sides AB and DE respectively.
Similarly, angles opposite to corresponding sides AC and EF are angles a and d respectively. So, angles a and d are corresponding angles.
Therefore, two sets of angles that are corresponding angles are:
[tex]\angle a \textrm{ and }\angle d; \angle b \textrm{ and }\angle c[/tex]

Answer:
The answer is a and d + b and c
Step-by-step explanation: