while a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the force?(unit=N)PLEASE HELP

Respuesta :

The magnitude of the force is 18.6 N

Explanation:

The work done by a force pushing/pulling an object is given by the equation:

[tex]W=Fd cos \theta[/tex]

where:

F is the magnitude of the force

d is the displacement of the object

[tex]\theta[/tex] is the angle between the direction of the force and the direction of the displacement

For the block in this problem, we have:

[tex]W=-17.8 J[/tex] is the work done

d = 1.35 m is the displacement

[tex]\theta=135^{\circ}[/tex] is the angle

Solving the equation for F, we find the magnitude of the force:

[tex]F=\frac{W}{dcos \theta}=\frac{-17.8}{(1.35)(cos 135)}=18.6 N[/tex]

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