Respuesta :
Answer:
[tex]6x + 5y = 15\:or\:y = -1\frac{1}{5}x + 3[/tex]
Step-by-step explanation:
First find the rate of change [slope]:
[tex]\frac{-y_1 + y_2}{-x_1 + x_2} = m[/tex]
[tex]\frac{3 + 15}{-5 - 10} = -\frac{18}{15} = -1\frac{1}{5}[/tex]
Then plug these coordinates into the Slope-Intercept Formula instead of the Point-Slope Formula because you get it done much swiftly. It does not matter which ordered pair you choose:
15 = −1⅕[−10] + b
12
[tex]3 = b \\ \\ y = -1\frac{1}{5}x + 3[/tex]
If you want it in Standard Form:
y = −1⅕x + 3
+1⅕x + 1⅕x
______________
[tex]1\frac{1}{5}x + y = 3[/tex][We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
5[1⅕x + y = 3]
[tex]6x + 5y = 15[/tex]
_______________________________________________
−3 = −1⅕[5] + b
−6
[tex]3 = b \\ \\ y = -1⅕x + 3[/tex]
y = −1⅕x + 3
+1⅕x + 1⅕x
______________
[tex]1⅕x + y = 3[/tex][We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
5[1⅕x + y = 3]
[tex]6x + 5y = 15[/tex]
** You see? I told you it did not matter which ordered pair you choose because you will always get the exact same result.
I am joyous to assist you anytime.
The equation for a line that passes through the points (5,-3) and (-10,15) will be 1.2x + y = 3.
What is the equation of a line passing through two points?
Suppose the given points are (x₁, y₁) and (x₂, y₂), then the equation of the straight line joining both two points is given by
[tex]\rm (y - y_1) = \left [ \dfrac{y_2 - y_1}{x_2 - x_1} \right ] (x -x_1)[/tex]
The equation for a line that passes through the points (5,-3) and (-10,15) will be
Then the points will be
(x₁, y₁) → (5, -3)
(x₂, y₂) → (-10, 15)
Then the equation of the line will be
y – (-3) = [(15 + 3)/(-10 - 5)](x – 5)
y + 3 = -1.2(x – 5)
1.2x + y = 3
Learn more about straight-line equations here:
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