Respuesta :

Answer:

[tex]6x + 5y = 15\:or\:y = -1\frac{1}{5}x + 3[/tex]

Step-by-step explanation:

First find the rate of change [slope]:

[tex]\frac{-y_1 + y_2}{-x_1 + x_2} = m[/tex]

[tex]\frac{3 + 15}{-5 - 10} = -\frac{18}{15} = -1\frac{1}{5}[/tex]

Then plug these coordinates into the Slope-Intercept Formula instead of the Point-Slope Formula because you get it done much swiftly. It does not matter which ordered pair you choose:

15 = −1⅕[−10] + b

12

[tex]3 = b \\ \\ y = -1\frac{1}{5}x + 3[/tex]

If you want it in Standard Form:

y = −1⅕x + 3

+1⅕x + 1⅕x

______________

[tex]1\frac{1}{5}x + y = 3[/tex][We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]

5[1⅕x + y = 3]

[tex]6x + 5y = 15[/tex]

_______________________________________________

−3 = −1⅕[5] + b

−6

[tex]3 = b \\ \\ y = -1⅕x + 3[/tex]

y = −1⅕x + 3

+1⅕x + 1⅕x

______________

[tex]1⅕x + y = 3[/tex][We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]

5[1⅕x + y = 3]

[tex]6x + 5y = 15[/tex]

** You see? I told you it did not matter which ordered pair you choose because you will always get the exact same result.

I am joyous to assist you anytime.

The equation for a line that passes through the points (5,-3) and (-10,15) will be 1.2x + y = 3.

What is the equation of a line passing through two points?

Suppose the given points are (x₁, y₁) and (x₂, y₂), then the equation of the straight line joining both two points is given by

[tex]\rm (y - y_1) = \left [ \dfrac{y_2 - y_1}{x_2 - x_1} \right ] (x -x_1)[/tex]

The equation for a line that passes through the points (5,-3) and (-10,15) will be

Then the points will be

(x₁, y₁) → (5, -3)

(x₂, y₂) → (-10, 15)

Then the equation of the line will be

y – (-3) = [(15 + 3)/(-10 - 5)](x – 5)

   y + 3 = -1.2(x – 5)

1.2x + y = 3

Learn more about straight-line equations here:

https://brainly.com/question/380976

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