300 milliliter a of [tex]25\%[/tex] NaOH solution would contain [tex]75 g[/tex] of NaOH
Solution:
Given volume percentage = [tex]25\%[/tex] Weight of solute = [tex]75 g[/tex]
Consider, [tex]\bold{\text {volume percentage}=\frac{\text {weight of solute in } g}{\text {volume of solution}} \times 100}[/tex]
[tex]\Rightarrow \text {Volume of solution is }=\left(\frac{75}{25}\right) \times 100[/tex]
[tex]\Rightarrow 3 \times 100[/tex]
Therefore, the answer is 300 ml.
