Teulally
1
in.
1 in.
(8, 13)
9. What is the perimeter of the
rectangle?

Answer:
[tex]5\dfrac{1}{2}\ inches[/tex]
Step-by-step explanation:
The perimeter of the rectangle is
[tex]P=2(\text{Length}+\text{Width})[/tex]
From the diagram,
Length = [tex]1 \frac{1}{2}[/tex] inches
Width = [tex]1\frac{1}{4}[/tex] inches
So, the perimeter is
[tex]P=2\left(1\dfrac{1}{2}+1\dfrac{1}{2}\right)[/tex]
Add numbers in brackets:
[tex]1+1=2\\ \\\dfrac{1}{2}+\dfrac{1}{4}=\dfrac{2}{4}+\dfrac{1}{4}=\dfrac{3}{4}\\ \\1\dfrac{1}{2}+1\dfrac{1}{4}=\dfrac{8}{4}+\dfrac{3}{4}=\dfrac{11}{4}[/tex]
Now, multiply it by 2:
[tex]P=2\cdot \dfrac{11}{4}=\dfrac{11}{2}=5\dfrac{1}{2}\ inches[/tex]