Answer:0.621 m/s
Explanation:
Given
mass of automobile [tex]m=2000 kg[/tex]
Effective spring constant [tex]k=4\times 10^6 N/m[/tex]
compression in spring[tex]x=1.39 cm[/tex]
Conserving Energy i.e. Kinetic energy of automobile=Elastic potential Energy of spring
[tex]\frac{mv^2}{2}=\frac{kx^2}{2}[/tex]
[tex]\frac{2000\cdot v^2}{2}=\frac{4\times 10^6\times (1.39\times 10^{-2})^2}{2}[/tex]
[tex]v^2=\frac{4\times 1.39^2\times 10^2}{2000}[/tex]
[tex]v=0.621 m/s[/tex]
