Answer:
See explanation below
Step-by-step explanation:
In a binomial distribution of n trials the expected value is
E = np
where p is the probability of “success” and the standard deviation is
[tex]\bf s=\sqrt{np(1-p)}[/tex]
So, if the expected value is 80, then
80 = 200p
hence
p=2/5
The standard deviation would be
[tex]\bf s=\sqrt{200*(2/5)*(3/5)}=6.9282[/tex]
as a consequence it is not possible for a binomial distribution of 200 trials with expected value 80 to have a standard deviation of 20.3