The resulting equation written in standard form is 16x²-22x+6=0.
Given that, y=12+2x is the linear equation and y=-16x²+24x+6 is a quadratic equation.
What is the standard form of the equation?
The standard form of the quadratic equation is ax² + bx + c = 0, where 'a' is the leading coefficient and it is a non-zero real number.
Now, y=-16x²+24x+6
Substitute, y=12+2x in y=-16x²+24x+6.
12+2x=-16x²+24x+6
⇒16x²-24x-6+12+2x=0
⇒16x²-22x+6=0
Therefore, the resulting equation written in standard form is 16x²-22x+6=0.
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