Answer:879.29 N-m
Explanation:
Given
mass of first child [tex]m_1=44 kg[/tex]
distance of first child from tree is [tex]r_1=1 m[/tex]
tree is inclined at an angle of [tex]\theta =27^{\circ}[/tex]
mass of second child [tex]m_1=27 kg[/tex]
distance of second child from tree is [tex]r_2=2.1 m[/tex]
Weight of first child[tex]=m_1g=431.2 kg[/tex]
Weight of second child[tex]=m_2g=264.6 kg[/tex]
Torque of first child weight[tex]=m_1g\cos \theta \cdot r_1[/tex]
[tex]T_1=44\times 9.8\times \cos 27\times 1=384.202 N-m[/tex]
Torque of second child weight[tex]=m_2g\cos \theta \cdot r_2[/tex]
[tex]T_2=27\times 9.8\times \cos 27\times 2.1=495.096 N-m[/tex]
Net torque [tex]T_{net}=T_1+T_2=384.202+495.096=879.29 N-m[/tex]
