While a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the force?(unit=N) PLEASE HELP. I WILL MARK BRAINLIEST FOR THE RIGHT ANSWER

Respuesta :

The magnitude of the force is 18.6 N

Explanation:

The work done by a force on an object is given by

[tex]W=Fd cos \theta[/tex]

where

F is the magnitude of the force

d is the displacement of the object

[tex]\theta[/tex] is the angle between the direction of the force and of the displacement

For the block in this problem, we have

[tex]W=-17.8 J[/tex] is the work done

d = 1.35 m is the displacement of the block

[tex]\theta=135^{\circ}[/tex] is the angle between the force and the displacement

Solving for F, we find the magnitude of the force:

[tex]F=\frac{W}{d cos \theta}=\frac{-17.8}{(1.35)(cos 135)}=18.6 N[/tex]

Learn more about work here:

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