Answer:
m= 1/2
Step-by-step explanation:
i think you could take 1/2 and multiply it by -3,-2 and get yor answer or you could use 1/2
The equation of the line that is parallel to the line [tex]y=\frac{1}{2} x-7[/tex] and passes through the point (-3, -2) is [tex]\bold{y=\frac{1}{2}(x-1)}[/tex]
Solution:
Given that the line passes through point (-3, -2)
The line is parallel to [tex]y=\frac{1}{2} x-7 \rightarrow (1)[/tex]
First let us find the slope of line, the point slope form is given as,
[tex]y-y_{1}=m\left(x-x_{1}\right) \rightarrow (2)[/tex]
where "m" is the slope of line
Comparing the (1) with (2) we get, m=\frac{1}{2}
The slopes of parallel lines are always equal. Hence the slope of line passing through (-3, -2) has the same slope as m=\frac{1}{2}
Now plug in m=\frac{1}{2} and in (2) to get the required equation of line,
[tex]y-(-2)=\frac{1}{2}(x-(-3)) \rightarrow y-(-2)=\frac{x}{2}+\frac{3}{2} \rightarrow y=\frac{x}{2}+\frac{3}{2}-2[/tex]
[tex]y=\frac{x}{2}+\frac{3}{2}-\frac{4}{2}[/tex]
[tex]y=\frac{x}{2}-\frac{1}{2} \rightarrow y=\frac{1}{2}(x-1)[/tex]
Thus, the equation of line parallel to given line is [tex]y=\frac{1}{2}(x-1)[/tex]
