Answer:
The coefficient of kinetic friction is 0.133
Step-by-step explanation:
Consider the provided information.
A toboggan slides down a hill and has a constant velocity. The angle of the hill is 7.60° with respect to the horizontal.
Let the coefficient of KE is μ.
It is given that the velocity is constant, therefore
[tex]\mu\ mg\ cos(\theta) = mg\ sin(\theta)[/tex]
[tex]\mu\ cos(\theta) =sin(\theta)[/tex]3
[tex]\mu =\frac{sin(\theta)}{cos(\theta)}[/tex]
[tex]\mu =tan(\theta)[/tex]
It is given that the angle of the hill is 7.60° with respect to the horizontal.
Substitute the value of 7.60° in above.
[tex]\mu =tan(7.60)[/tex]
[tex]\mu\approx0.133[/tex]
Therefore, the coefficient of kinetic friction is 0.133
