At 9:00am, a dog chased a squirrel 8 miles north. The dog gave up and stopped chasing the squirrel at 10:00am. What was the average velocity of the dog while he was chasing the squirrel?


8 mph south

16 mph north

Respuesta :

Answer:

16 mph north ^^

DONT HATE, if im wrong!!!!!!!! have a wonderful day~~

Answer:

8 [tex]\frac{m}{s}[/tex] was the average velocity of the dog while he was chasing the squirrel

Explanation:

Speed ​​is a change of position of a body over time. Then the speed is defined as the amount of space traveled per unit of time with which a body travels in a certain direction and direction.

Its unit of measure in the International System (S.I.) is the meter per second (m/s)

[tex]velocity = \frac{distance traveled}{time}[/tex]

In this case you know that:

  • Start time = 9.00 am
  • Final time = 10.00 am

Then, the change in time from 9 - 10am is 1 hour.

  • Distance traveled = 8 miles north

The dog chased the squirrel for 1 hour a distance of 8 miles and you can assume that his speed was constant.

Finally:

[tex]velocity=\frac{distance traveled}{time}[/tex]

[tex]velocity=\frac{8 miles}{1 hour}[/tex]

[tex]velocity= 8\frac{m}{s}[/tex]

8 [tex]\frac{m}{s}[/tex] was the average velocity of the dog while he was chasing the squirrel