For this case we have that the distance between two points is given by the following formula:
[tex]d = \sqrt {(x_ {2} -x_ {1})^ 2+(y_ {2} -y_ {1}) ^ 2}[/tex]
We have the following points:
[tex](x_ {1}, y_ {1}): (-1,4)\\(x_ {2}, y_ {2}): (2,0)[/tex]
Substituting we have:
[tex]d = \sqrt {(2 - (- 1)) ^ 2+ (0-4) ^ 2}\\d = \sqrt {(2 + 1) ^ 2 + (- 4) ^ 2}\\d = \sqrt {(3) ^ 2 + (- 4) ^ 2}\\d = \sqrt {9 + 16}\\d = \sqrt {25}\\d = 5[/tex]
Thus, the distance between the points is 5 units.
Answer:
[tex]d = 5[/tex]
