Bob, who has a mass of 79 kg , can throw a 510 g rock with a speed of 34 m/s . The distance through which his hand moves as he accelerates the rock forward from rest until he releases it is 1.0 m. Part A What constant force must Bob exert on the rock to throw it with this speed?

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07-11-2019
Physics

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Bob, who has a mass of 79 kg , can throw a 510 g rock with a speed of 34 m/s . The distance through which his hand moves as he accelerates the rock forward from rest until he releases it is 1.0 m. Part A What constant force must Bob exert on the rock to throw it with this speed?

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aristeus aristeus · Answer 1 · 2019-11-08T07:09:16+01:00

aristeus aristeus

08-11-2019

Answer:

Force will be 2947.8 N

Explanation:

We have given that mass of the rock m = 510 gram = 0.510 kg

Final velocity v = 34 m/sec

Distance s = 1 m

Initial velocity u = 0 m/sec

From third equation of motion we know that [tex]v^2=u^2+2as[/tex]

[tex]34^2=0^2+2\times a\times 1[/tex]

[tex]a=578m/sec^2[/tex]

From newton's law of motion we know that F = ma

So force [tex]F=0.510\times 578=2947.8N[/tex]

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Netta00 Netta00 · Answer 2 · 2019-11-08T08:17:07+01:00

Netta00 Netta00

08-11-2019

Answer:

F=294.78 N

Explanation:

Given that

M= 79 kg

m= 510 g= 0.51 kg

Initial speed u = 0 m/s

Final speed ,v= 34 m/s

d= 1 m

We know that

v²=u²+ 2 a d

By putting the values

34²= 0 ² + 2 x a x 1

a= 578 m/s²

From second law of Newton's

F= m a

By putting the values

F= 0.51 x 578 N

F=294.78 N

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