Answer:half of shorter Pipe
Explanation:
Fluid is Flowing through two horizontal pipes with pressure difference
[tex]P_1-P_2=\Delta P[/tex]
Both pipes have same radius
Length of one Pipe is twice of other
Let Longer Pipe be denote by 1 and smaller by 2
From Hagen Poiseuille equation
[tex]\Delta P=\frac{128\mu L\cdot Q}{\pi D^4}[/tex]
Where [tex]\mu =[/tex]viscosity of medium
L=length of Pipe
Q=discharge
D=diameter
For longer Pipe
[tex]\Delta P=\frac{128\mu 2L\cdot Q_1}{\pi \cdot D^4}[/tex]----1
For smaller Pipe
[tex]\Delta P=\frac{128\mu L\cdot Q_2}{\pi \cdot D^4}[/tex]------2
From 1 & 2 we get
[tex]2L\cdot Q_1=L\cdot Q_2[/tex]
[tex]Q_2=2Q_1[/tex]
volume flow rate of longer pipe is half of smaller pipe
