Answer:
The answer to your question is: letter A.
Explanation:
To solve this question, we must consider the total number of electrons that can be placed in each orbital.
Orbital Number of electrons
s 2
p 6
d 10
f 14
Options given
A. 1s² 2s² 2p⁶ 3s² This electron configuration is correct because
is in agreement with the number of electrons
allowed in each orbital and the correct order
of them.
B. 1s² 2s² 2p⁶ 3s² 3d⁴ This electron configuration is incorrect because
3d⁴ goes after 3p.
C. 1s² 2s² 2d¹⁰ 2p³ This option is incorrect because 2d¹⁰ does not
exist.
D. 1s² 2s^s 2p³ 2d¹⁰ This option has 2 mistakes, s as a power does
not exist and 2d¹⁰ is also incorrect.
