A force vec F =F x hat i +F y hat j acts on a particle that undergoes a displacement of vec s =s x hat i +s y hat j where F x =7 N , F y =-3 N , s x =4 m , and s y =1 m . Find the work done by the force on the particle . Answer in units of J.

Respuesta :

ustsr

The work done by the force on the particle is 25 Joule

Further explanation

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

[tex]\large {\boxed {F = ma }[/tex]

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

[tex]\overrightarrow{F} = 7 \widehat{i} - 3 \widehat{j}[/tex]

[tex]\overrightarrow{s} = 4 \widehat{i} + 1 \widehat{j}[/tex]

Unknown:

W = ?

Solution:

[tex]W = \overrightarrow{F} \cdot \overrightarrow{s}[/tex]

[tex]W = (7 \widehat{i} - 3 \widehat{j}) \cdot (4 \widehat{i} + 1 \widehat{j})[/tex]

[tex]W = 7(4) - 3(1)[/tex]

[tex]W = 28 - 3[/tex]

[tex]W = 25 \texttt{ Joule}[/tex]

[tex]\texttt{ }[/tex]

Conclusion:

The work done by the force on the particle is 25 Joule

[tex]\texttt{ }[/tex]

Learn more

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  • Newton's Law of Motion: https://brainly.com/question/10431582
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Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

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