Answer:h=7.22 m
Explanation:
Given
mass of firefighter [tex]m=88 kg[/tex]
Frictional Force [tex]F=800 N[/tex]
average speed at bottom [tex]v=3.2 m/s[/tex]
Let h be the height of Pole
net force on Firefighter is
[tex]F_{net}=88\times 9.8-800=62.4[/tex]
therefore net acceleration is
[tex]a_{net}=\frac{62.4}{88}=0.709 m/s^2[/tex]
using [tex]v^2-u^2=2ah[/tex]
here [tex]v=3.2 m/s[/tex]
[tex]u=0[/tex]
[tex](3.2)^2-0=2\times 0.709\times h[/tex]
[tex]h=\frac{10.24}{1.418}[/tex]
[tex]h=7.22 m[/tex]
