Newly occupied volume is 7.672L by N2 gas.
Explanation:-
Given
V= 9.20 L, T(i) = T (f) = 294 K, P (i) = 0.959 atm, P (f) = 1.15 atm
To Find V (f)
Solution
According to the gas equation
PV= nRT
Where P=Pressure
V=Volume
n=No of moles
R=Universal gas constant
T=Temperature
Also we know the relation between pressure, volume and temperature as
PV/T = constant
[tex]\frac{p(i) V(i) \times p(f) V(f)}{T(i) \times T(f)}[/tex]
[tex]V(f)=[P(i) V(i) T(f)] \div[T(i) P(f)][/tex]
Where P(i)V(i)/T(i) are the initial values of Pressure, Volume and Temperature.
P(f)V(f)/T(f) are the final values of Pressure, Temperature and Volume.
Substitute the known values in the equation we get
= [tex]\frac{0.959 \times 9,2 \times 294}{294 \times 1.15}[/tex]
=[tex]2574.94 \div 338.1[/tex]
= 7.672 L
Thus the final volume of the system is 7.672 L
