Answer:
[tex]p_{f}=99x10^6 N*s[/tex]
Explanation:
When a force is applied to an object over a certain period of time, it is said to apply an impulse to the object. The magnitude of the impulse is given by:
J=F*Δt
When an impulse is provided to an object, the momentum of the object will change, as in:
J=Δp=[tex]p_{f}-p_{i}[/tex]
So given:
Initial momentum
[tex]P_{i}=5.19x10^7 \frac{kg*m}{s}[/tex]
Applied force
[tex]F=2.0x10^6 N[/tex]
J=[tex]p_{f}-p_{i}[/tex]
F*Δt=[tex]p_{f}-p_{i}[/tex]
[tex]p_{f}=2.0x10^6N*12s+7.5x10^7 N*s[/tex]
[tex]p_{f}=99x10^6 N*s[/tex]